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29 March 2011 - 07:10 AMHI Moati,
Dibs on a custom vest. Email to follow tonight.
14 March 2011 - 07:52 AMTrue
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24 February 2011 - 07:55 PMFalse.
TNP is eating pizza for dinner.
24 February 2011 - 06:44 PMI'm not sure if you are still trying to solve this but here is how I would do it.
I will define the variable 't' = "the time spent traveling"
As you may already know your problem describes a right angle triangle with the following sides:
1. A = Long side adjacent to the 90░ = 500
2. B = Short side adjacent to the 90░ = 3.7Ět (or 3.7 times 't')
3. C = Hypotenuse = 10Ět
Setting up the standard equation for a right angle triangle (Pythagoras Theorem) A^2 + B^2 = C^2 gives the following relation ship (the '^' hat symbol indicates "raised to the power of" so that each side is squared):
Equation: 500^2 + (3.7Ět)^2 = (10Ět)^2
Steps to solve: 250,000 + 13.69Ět^2 = 100Ět^2
250,000 = 86.31Ět^2
t^2 = 250,000/86.31 = 2896.54
t= 53.8 seconds
Solving for the angle is easy if you use the sine function. I'll define "theta" as the angle of traverse.
sin(theta)= opposite/hypotenuse = (3.7Ět)/(10Ět)= 0.37
so theta = asin(3.7) = 21.72░
You could also use cosine or tangent but you have to multiply 't' into one of the velocities which is slightly longer math.
I hope this helps.
24 February 2011 - 06:16 PMTrue.
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